What is the answer to log_{2}(x+4)=log_{2}(x-2)+3 ?

The answer to log_{2}(x+4)=log_{2}(x-2)+3 is x= 20/7

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log_{2}(x+4)=log_{2}(x-2)+3

lo g_{2} (x + 4) = lo g_{2} (x - 2) + 3

x = \frac{20}{7}

Decimal Notation

x = 2.85714 \dots

Solution steps

lo g_{2} (x + 4) = lo g_{2} (x - 2) + 3

Apply log rules

x + 4 = (x - 2) \cdot 8

Solve

x + 4 = (x - 2) \cdot 8 : x = \frac{20}{7}

x = \frac{20}{7}

Verify Solutions:

x = \frac{20}{7}

True

The solution is

x = \frac{20}{7}

lo g_{3 - 2 x} (6 x^{2} - 11 x + 6) = 2

- 1 = lo g_{10} (x)

ln (x) = - x

ln (x) = - 4

ln (x) = - 5

What is the answer to log_{2}(x+4)=log_{2}(x-2)+3 ?
The answer to log_{2}(x+4)=log_{2}(x-2)+3 is x= 20/7
Solve for x: log_{2}(x+4)=log_{2}(x-2)+3
The solution is x= 20/7