What is the answer to ln(xy)=ln(x)+ln(y) ?

The answer to ln(xy)=ln(x)+ln(y) is No Solution for x\in\mathbb{R}

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ln(xy)=ln(x)+ln(y)

ln (x y) = ln (x) + ln (y)

No Solution for x \in R

Solution steps

ln (x y) = ln (x) + ln (y)

Apply log rules

x y = x y

Both sides are equal

True for all x

Verify Solutions:

x < 0

False

, x = 0

False

, x > 0

False

The solution is

No Solution for x \in R

ln (x) + x = 1

lo g_{2 x} (16) = ln (2 x)

lo g_{3} (x^{2} - 6 x) = 3

2 lo g_{2} (x) + lo g_{2} (a) = 0

6 = - lo g_{10} (x)

What is the answer to ln(xy)=ln(x)+ln(y) ?
The answer to ln(xy)=ln(x)+ln(y) is No Solution for x\in\mathbb{R}