What is the answer to log_{10}(2x)+log_{10}(x)=11 ?

The answer to log_{10}(2x)+log_{10}(x)=11 is x=10^{(11-log_{10}(2))/2}

Solve for x: log_{10}(2x)+log_{10}(x)=11

The solution is x=10^{(11-log_{10}(2))/2}

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lo g_{10} (2 x) + lo g_{10} (x) = 11

x = 1 0^{\frac{11 - l o g _{10} ( 2 )}{2}}

Decimal Notation

x = 223606.79774 \dots

Solution steps

lo g_{10} (2 x) + lo g_{10} (x) = 11

Apply log rules

x = 1 0^{\frac{11 - l o g _{10} ( 2 )}{2}}

Verify Solutions:

x = 1 0^{\frac{11 - l o g _{10} ( 2 )}{2}}

True

The solution is

x = 1 0^{\frac{11 - l o g _{10} ( 2 )}{2}}

lo g_{4} (- 2 x + 11) = 2

lo g_{3} (x) + lo g_{9} (x) = 12

x, z = ln (4 - x - y)

x, y = 4 ln (x + c)

lo g_{2} (1 - x) = 2

What is the answer to log_{10}(2x)+log_{10}(x)=11 ?
The answer to log_{10}(2x)+log_{10}(x)=11 is x=10^{(11-log_{10}(2))/2}
Solve for x: log_{10}(2x)+log_{10}(x)=11
The solution is x=10^{(11-log_{10}(2))/2}