What are the solutions to the equation 6x^2+17x=3 ?

The solutions to the equation 6x^2+17x=3 are x= 1/6 ,x=-3

Find the zeros of 6x^2+17x=3

The zeros of 6x^2+17x=3 are x= 1/6 ,x=-3

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6 x^{2} + 17 x = 3

x = \frac{1}{6}, x = - 3

Decimal Notation

x = 0.16666 \dots, x = - 3

Solution steps

6 x^{2} + 17 x = 3

Move

3

to the left side

6 x^{2} + 17 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

1 7^{2} - 4 \cdot 6 (- 3) = 19

x_{1, 2} = \frac{- 17 \pm 19}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 17 + 19}{2 \cdot 6}, x_{2} = \frac{- 17 - 19}{2 \cdot 6}

x = \frac{- 17 + 19}{2 \cdot 6} : \frac{1}{6}

x = \frac{- 17 - 19}{2 \cdot 6} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{6}, x = - 3

\frac{5.0 5 ^{2} - 5 ( 5.05 )}{5.0 5 ^{2} - 25}

3 (x + 4)^{2} - 3 = 0

n^{2} + 17 n + 70

10 n + 12 - 9 - 7 n + 4 n = 31

m^{2} - 100 = 0

What are the solutions to the equation 6x^2+17x=3 ?
The solutions to the equation 6x^2+17x=3 are x= 1/6 ,x=-3
Find the zeros of 6x^2+17x=3
The zeros of 6x^2+17x=3 are x= 1/6 ,x=-3