What is the answer to (ln(x)-1)/(ln^2(x))=0 ?

The answer to (ln(x)-1)/(ln^2(x))=0 is x=e

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(ln(x)-1)/(ln^2(x))=0

\frac{ln ( x ) - 1}{ln ^{2} ( x )} = 0

x = e

Decimal Notation

x = 2.71828 \dots

Solution steps

\frac{ln ( x ) - 1}{ln ^{2} ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

ln (x) - 1 = 0

Move

1

to the right side

ln (x) = 1

Apply log rules

x = e

Verify Solutions:

x = e

True

The solution is

x = e

- lo g_{10} (x) = 3

ln (x^{2} - 4 x + 5) = 0

lo g_{3} (4 x) - lo g_{3} (8) = 3

x, lo g_{2} (x) = y + c

lo g_{x - 1} (4 + 3 x - x^{2}) = 2

What is the answer to (ln(x)-1)/(ln^2(x))=0 ?
The answer to (ln(x)-1)/(ln^2(x))=0 is x=e
Solve for x: (ln(x)-1)/(ln^2(x))=0
The solution is x=e