What is the answer to 0.52=log_{10}(x) ?

The answer to 0.52=log_{10}(x) is x=10^{0.52}

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0.52=log_{10}(x)

0.52 = lo g_{10} (x)

x = 1 0^{0.52}

Decimal Notation

x = 3.31131 \dots

Solution steps

0.52 = lo g_{10} (x)

Apply log rules

1 0^{0.52} = x

Switch sides

x = 1 0^{0.52}

lo g_{7} (x) = 0

3 lo g_{10} (2 x) = 3 + lo g_{10} (27)

lo g_{2} (w + 1) = 3

lo g_{3} (4 x) - 2 lo g_{3} (x) = 2

ln (x^{2} + 1) - 3 ln (x) = ln (2)

What is the answer to 0.52=log_{10}(x) ?
The answer to 0.52=log_{10}(x) is x=10^{0.52}
Solve for x: 0.52=log_{10}(x)
The solution is x=10^{0.52}