What is the answer to log_{10}(2x-1)= 1/2 ?

The answer to log_{10}(2x-1)= 1/2 is x=(sqrt(10)+1)/2

Solve for x: log_{10}(2x-1)= 1/2

The solution is x=(sqrt(10)+1)/2

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lo g_{10} (2 x - 1) = \frac{1}{2}

x = \frac{10 + 1}{2}

Decimal Notation

x = 2.08113 \dots

Solution steps

lo g_{10} (2 x - 1) = \frac{1}{2}

Apply log rules

2 x - 1 = 10

Solve

2 x - 1 = 10 : x = \frac{10 + 1}{2}

x = \frac{10 + 1}{2}

lo g_{10} (x) = - 6

lo g_{10} (x) = 11

lo g_{10} (4 x) = 3

x = lo g_{2} (x)

lo g_{10} (2 x) = lo g_{10} (x - 5) + 2

What is the answer to log_{10}(2x-1)= 1/2 ?
The answer to log_{10}(2x-1)= 1/2 is x=(sqrt(10)+1)/2
Solve for x: log_{10}(2x-1)= 1/2
The solution is x=(sqrt(10)+1)/2