What is the answer to log_{4}(x)+log_{8}(x)=1 ?

The answer to log_{4}(x)+log_{8}(x)=1 is x=8^{2/5}

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log_{4}(x)+log_{8}(x)=1

lo g_{4} (x) + lo g_{8} (x) = 1

x = 8^{\frac{2}{5}}

Decimal Notation

x = 2.29739 \dots

Solution steps

lo g_{4} (x) + lo g_{8} (x) = 1

Apply log rules

x = 8^{\frac{2}{5}}

Verify Solutions:

x = 8^{\frac{2}{5}}

True

The solution is

x = 8^{\frac{2}{5}}

lo g_{m} (\frac{8}{125}) = - 3

lo g_{5} (x) = 6

lo g_{5} (x) = 5

0.57 = lo g_{10} (x)

lo g_{x} (4) = - \frac{2}{5}

What is the answer to log_{4}(x)+log_{8}(x)=1 ?
The answer to log_{4}(x)+log_{8}(x)=1 is x=8^{2/5}
Solve for x: log_{4}(x)+log_{8}(x)=1
The solution is x=8^{2/5}