What is the answer to ln(4x+1)-ln(3)=5 ?

The answer to ln(4x+1)-ln(3)=5 is x=(3e^5-1)/4

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ln(4x+1)-ln(3)=5

ln (4 x + 1) - ln (3) = 5

x = \frac{3 e ^{5} - 1}{4}

Decimal Notation

x = 111.05986 \dots

Solution steps

ln (4 x + 1) - ln (3) = 5

Move

ln (3)

to the right side

ln (4 x + 1) = 5 + ln (3)

Apply log rules

4 x + 1 = 3 e^{5}

Solve

4 x + 1 = 3 e^{5} : x = \frac{3 e ^{5} - 1}{4}

x = \frac{3 e ^{5} - 1}{4}

Verify Solutions:

x = \frac{3 e ^{5} - 1}{4}

True

The solution is

x = \frac{3 e ^{5} - 1}{4}

lo g_{2} (1 - y) - lo g_{2} (5 + y) = 3

lo g_{x} (3) = 2

lo g_{5} (x - 7) = 1

ln (x) - x + 2 = 0

- 2 lo g_{5} (7 x) = 2

What is the answer to ln(4x+1)-ln(3)=5 ?
The answer to ln(4x+1)-ln(3)=5 is x=(3e^5-1)/4
Solve for x: ln(4x+1)-ln(3)=5
The solution is x=(3e^5-1)/4