What is the answer to log_{2}(x+6)+log_{2}(x-1)=3 ?

The answer to log_{2}(x+6)+log_{2}(x-1)=3 is x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x+6)+log_{2}(x-1)=3

lo g_{2} (x + 6) + lo g_{2} (x - 1) = 3

x = 2

Solution steps

lo g_{2} (x + 6) + lo g_{2} (x - 1) = 3

Apply log rules

(x + 6) (x - 1) = 8

Solve

(x + 6) (x - 1) = 8 : x = 2, x = - 7

x = 2, x = - 7

Verify Solutions:

x = 2

True

, x = - 7

False

The solution is

x = 2

lo g_{10} (x) = 0.6

lo g_{2} (x) = 5 - lo g_{2} (x + 4)

ln (x) - ln (x + 1) = 2

lo g_{10} (7 x - 12) = 2 lo g_{10} (x)

lo g_{2} (lo g_{2} (x)) = 2

What is the answer to log_{2}(x+6)+log_{2}(x-1)=3 ?
The answer to log_{2}(x+6)+log_{2}(x-1)=3 is x=2
Solve for x: log_{2}(x+6)+log_{2}(x-1)=3
The solution is x=2