What is the answer to ln(x^2+1)=1+2ln(x) ?

The answer to ln(x^2+1)=1+2ln(x) is x=sqrt(1/(e-1))

Solve for x: ln(x^2+1)=1+2ln(x)

The solution is x=sqrt(1/(e-1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln (x^{2} + 1) = 1 + 2 ln (x)

x = \frac{1}{e - 1}

Decimal Notation

x = 0.76287 \dots

Solution steps

ln (x^{2} + 1) = 1 + 2 ln (x)

Apply log rules

x^{2} + 1 = e x^{2}

Solve

x^{2} + 1 = e x^{2} : x = \frac{1}{e - 1}, x = - \frac{1}{e - 1}

x = \frac{1}{e - 1}, x = - \frac{1}{e - 1}

Verify Solutions:

x = \frac{1}{e - 1}

True

, x = - \frac{1}{e - 1}

False

The solution is

x = \frac{1}{e - 1}

ln (x) + ln (x - 8) = 4

ln (3 x + 4) = 2 ln (x + 1)

2 lo g_{5} (x) = 3 lo g_{5} (4)

lo g_{x} (64) = \frac{1}{2}

lo g_{3} (x^{2}) = 2

What is the answer to ln(x^2+1)=1+2ln(x) ?
The answer to ln(x^2+1)=1+2ln(x) is x=sqrt(1/(e-1))
Solve for x: ln(x^2+1)=1+2ln(x)
The solution is x=sqrt(1/(e-1))