What is the answer to log_{6}(x-2)+log_{6}(x+3)=2 ?

The answer to log_{6}(x-2)+log_{6}(x+3)=2 is x=6

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log_{6}(x-2)+log_{6}(x+3)=2

lo g_{6} (x - 2) + lo g_{6} (x + 3) = 2

x = 6

Solution steps

lo g_{6} (x - 2) + lo g_{6} (x + 3) = 2

Apply log rules

(x - 2) (x + 3) = 36

Solve

(x - 2) (x + 3) = 36 : x = 6, x = - 7

x = 6, x = - 7

Verify Solutions:

x = 6

True

, x = - 7

False

The solution is

x = 6

lo g_{10} (n) = 1000000

lo g_{10} (x + 2) - (x - 1) = 1

0.49 = lo g_{10} (x)

20 lo g_{10} (x) = 40

lo g_{2} (t) + lo g_{2} (t + 2) = 3

What is the answer to log_{6}(x-2)+log_{6}(x+3)=2 ?
The answer to log_{6}(x-2)+log_{6}(x+3)=2 is x=6
Solve for x: log_{6}(x-2)+log_{6}(x+3)=2
The solution is x=6