What is the answer to log_{10}(3+2log_{10}(1+x))=0 ?

The answer to log_{10}(3+2log_{10}(1+x))=0 is x=-9/10

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log_{10}(3+2log_{10}(1+x))=0

lo g_{10} (3 + 2 lo g_{10} (1 + x)) = 0

x = - \frac{9}{10}

Decimal Notation

x = - 0.9

Solution steps

lo g_{10} (3 + 2 lo g_{10} (1 + x)) = 0

Apply log rules

1 + x = \frac{1}{10}

Solve

1 + x = \frac{1}{10} : x = - \frac{9}{10}

x = - \frac{9}{10}

Verify Solutions:

x = - \frac{9}{10}

True

The solution is

x = - \frac{9}{10}

lo g_{a} (6) = \frac{1}{2}

y, ln (y) = 2 t - 3

lo g_{3} (25) = 2 lo g_{3} (x)

lo g_{10} (x - 2) = 0

- c + 1 + c ln (c) = 1

What is the answer to log_{10}(3+2log_{10}(1+x))=0 ?
The answer to log_{10}(3+2log_{10}(1+x))=0 is x=-9/10
Solve for x: log_{10}(3+2log_{10}(1+x))=0
The solution is x=-9/10