What are the solutions to the equation x^2-x= 2/9-(2x)/3 ?

The solutions to the equation x^2-x= 2/9-(2x)/3 are x= 2/3 ,x=-1/3

Find the zeros of x^2-x= 2/9-(2x)/3

The zeros of x^2-x= 2/9-(2x)/3 are x= 2/3 ,x=-1/3

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x^{2} - x = \frac{2}{9} - \frac{2 x}{3}

x = \frac{2}{3}, x = - \frac{1}{3}

Decimal Notation

x = 0.66666 \dots, x = - 0.33333 \dots

Solution steps

x^{2} - x = \frac{2}{9} - \frac{2 x}{3}

Find Least Common Multiplier of

9, 3 : 9

Multiply by LCM=

9

x^{2} \cdot 9 - x \cdot 9 = \frac{2}{9} \cdot 9 - \frac{2 x}{3} \cdot 9

Simplify

9 x^{2} - 9 x = 2 - 6 x

Move

6 x

to the left side

9 x^{2} - 3 x = 2

Move

2

to the left side

9 x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

(- 3)^{2} - 4 \cdot 9 (- 2) = 9

x_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 9}, x_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 9}

x = \frac{- ( - 3 ) + 9}{2 \cdot 9} : \frac{2}{3}

x = \frac{- ( - 3 ) - 9}{2 \cdot 9} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{1}{3}

\frac{6 x + 1}{12} - \frac{x - 13}{9} = \frac{5 x - 3}{2} + \frac{x}{30}

12 z^{2} + 1 z - 1 = 0

9 \cdot \frac{4}{3}

12 l^{2} + 48 l - 826 = 0

441

What are the solutions to the equation x^2-x= 2/9-(2x)/3 ?
The solutions to the equation x^2-x= 2/9-(2x)/3 are x= 2/3 ,x=-1/3
Find the zeros of x^2-x= 2/9-(2x)/3
The zeros of x^2-x= 2/9-(2x)/3 are x= 2/3 ,x=-1/3