What is the answer to log_{2}(9-2^x)=3-x ?

The answer to log_{2}(9-2^x)=3-x is x=0,x=3

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log_{2}(9-2^x)=3-x

lo g_{2} (9 - 2^{x}) = 3 - x

x = 0, x = 3

Solution steps

lo g_{2} (9 - 2^{x}) = 3 - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

2^{l o g_{2} (9 - 2^{x})} = 2^{3 - x}

Simplify

2^{l o g_{2} (9 - 2^{x})} : 9 - 2^{x}

9 - 2^{x} = 2^{3 - x}

Solve

9 - 2^{x} = 2^{3 - x} : x = 0, x = 3

x = 0, x = 3

Verify Solutions:

x = 0

True

, x = 3

True

The solutions are

x = 0, x = 3

8 ln (9) = ln (a) + (12) ln (3)

3 lo g_{\frac{2}{3}} (x) + 12 = 0

lo g_{2} (x + 7) - lo g_{2} (x - 11) = 2

lo g_{5} (x - 4) = 0

ln (3 x - 2) = 5

What is the answer to log_{2}(9-2^x)=3-x ?
The answer to log_{2}(9-2^x)=3-x is x=0,x=3
Solve for x: log_{2}(9-2^x)=3-x
The solution is x=0,x=3