What is the answer to 4ln(4x)=ln(2x) ?

The answer to 4ln(4x)=ln(2x) is x= 1/(e^{\frac{7ln(2)){3}}}

Solve for x: 4ln(4x)=ln(2x)

The solution is x= 1/(e^{\frac{7ln(2)){3}}}

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4 ln (4 x) = ln (2 x)

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Decimal Notation

x = 0.19842 \dots

Solution steps

4 ln (4 x) = ln (2 x)

Apply log rules

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Verify Solutions:

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

True

The solution is

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

\frac{1}{x} = ln (x)

ln (x) - x = 0

lo g_{x} (5) = \frac{1}{4}

lo g_{9} (r - 8) = 2

2 = lo g_{10} (\frac{x}{1000})

What is the answer to 4ln(4x)=ln(2x) ?
The answer to 4ln(4x)=ln(2x) is x= 1/(e^{\frac{7ln(2)){3}}}
Solve for x: 4ln(4x)=ln(2x)
The solution is x= 1/(e^{\frac{7ln(2)){3}}}