What is the answer to log_{3}(x-2)+log_{3}(x+4)=3 ?

The answer to log_{3}(x-2)+log_{3}(x+4)=3 is x=5

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log_{3}(x-2)+log_{3}(x+4)=3

lo g_{3} (x - 2) + lo g_{3} (x + 4) = 3

x = 5

Solution steps

lo g_{3} (x - 2) + lo g_{3} (x + 4) = 3

Apply log rules

(x - 2) (x + 4) = 27

Solve

(x - 2) (x + 4) = 27 : x = 5, x = - 7

x = 5, x = - 7

Verify Solutions:

x = 5

True

, x = - 7

False

The solution is

x = 5

3 + 2 lo g_{2} (x) = lo g_{2} (14 x - 3)

lo g_{2} (5 x - 3) = 5

0.53 = lo g_{10} (x)

lo g_{10} (x^{2} - 3) = 0

ln (7 x + e) = 3

What is the answer to log_{3}(x-2)+log_{3}(x+4)=3 ?
The answer to log_{3}(x-2)+log_{3}(x+4)=3 is x=5
Solve for x: log_{3}(x-2)+log_{3}(x+4)=3
The solution is x=5