What is the answer to ln(t)-ln(t+1)=2 ?

The answer to ln(t)-ln(t+1)=2 is No Solution for t\in\mathbb{R}

Solve for t: ln(t)-ln(t+1)=2

The solution is No Solution for t\in\mathbb{R}

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ln (t) - ln (t + 1) = 2

No Solution for t \in R

Solution steps

ln (t) - ln (t + 1) = 2

Add

ln (t + 1)

to both sides

ln (t) - ln (t + 1) + ln (t + 1) = 2 + ln (t + 1)

Simplify

ln (t) = 2 + ln (t + 1)

Apply log rules

t = e^{2} (t + 1)

Solve

t = e^{2} (t + 1) : t = \frac{e ^{2}}{1 - e ^{2}}

t = \frac{e ^{2}}{1 - e ^{2}}

Verify Solutions:

t = \frac{e ^{2}}{1 - e ^{2}}

False

The solution is

No Solution for t \in R

lo g_{3} (2 x) = - 2

y, x^{2} = ln (y) - ln (3)

lo g_{9} (x + 8) + lo g_{9} (x + 7) = 2

0.74 = lo g_{10} (x)

0.77 = lo g_{10} (x)

What is the answer to ln(t)-ln(t+1)=2 ?
The answer to ln(t)-ln(t+1)=2 is No Solution for t\in\mathbb{R}
Solve for t: ln(t)-ln(t+1)=2
The solution is No Solution for t\in\mathbb{R}