What is the answer to log_{x}(2x^{x-2}-1)+4=2x ?

The answer to log_{x}(2x^{x-2}-1)+4=2x is No Solution for x\in\mathbb{R}

Solve for x: log_{x}(2x^{x-2}-1)+4=2x

The solution is No Solution for x\in\mathbb{R}

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lo g_{x} (2 x^{x - 2} - 1) + 4 = 2 x

No Solution for x \in R

Solution steps

lo g_{x} (2 x^{x - 2} - 1) + 4 = 2 x

Move

4

to the right side

lo g_{x} (2 x^{x - 2} - 1) = 2 x - 4

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

x^{l o g_{x} (2 x^{x - 2} - 1)} = x^{2 x - 4}

Simplify

x^{l o g_{x} (2 x^{x - 2} - 1)} : 2 x^{x - 2} - 1

2 x^{x - 2} - 1 = x^{2 x - 4}

Solve

2 x^{x - 2} - 1 = x^{2 x - 4} :

No Solution for

x \in R

No Solution for x \in R

lo g_{10} (x - 3) = 1 - lo g_{10} (x)

- 1 + ln (x - 3) = 0

lo g_{5} (x) + 12 lo g_{x} (5) = 7

lo g_{3} (x + 3) + lo g_{3} (x - 5) = 2

ln (x) - x = - 2

What is the answer to log_{x}(2x^{x-2}-1)+4=2x ?
The answer to log_{x}(2x^{x-2}-1)+4=2x is No Solution for x\in\mathbb{R}
Solve for x: log_{x}(2x^{x-2}-1)+4=2x
The solution is No Solution for x\in\mathbb{R}