What is the answer to log_{x}(49)=log_{7}(343)-1 ?

The answer to log_{x}(49)=log_{7}(343)-1 is x=7

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log_{x}(49)=log_{7}(343)-1

lo g_{x} (49) = lo g_{7} (343) - 1

x = 7

Solution steps

lo g_{x} (49) = lo g_{7} (343) - 1

Apply log rules

\frac{1}{lo g _{49} ( x )} = lo g_{7} (343) - 1

Multiply both sides by

lo g_{49} (x)

\frac{1}{lo g _{49} ( x )} lo g_{49} (x) = lo g_{7} (343) lo g_{49} (x) - 1 \cdot lo g_{49} (x)

Apply log rules

x = 7

Verify Solutions:

x = 7

True

The solution is

x = 7

9 = 10 lo g_{10} (x)

lo g_{3} (x - 1) - lo g_{3} (x + 2) = 2

lo g_{\frac{1}{3}} (x) = - 2

lo g_{10} (x) = 1.8965

8 n^{2} = 64 n lo g_{10} (n)

What is the answer to log_{x}(49)=log_{7}(343)-1 ?
The answer to log_{x}(49)=log_{7}(343)-1 is x=7
Solve for x: log_{x}(49)=log_{7}(343)-1
The solution is x=7