What are the solutions to the equation (x-5)^2+5=49 ?

The solutions to the equation (x-5)^2+5=49 are x=2sqrt(11)+5,x=-2sqrt(11)+5

Find the zeros of (x-5)^2+5=49

The zeros of (x-5)^2+5=49 are x=2sqrt(11)+5,x=-2sqrt(11)+5

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(x - 5)^{2} + 5 = 49

x = 211 + 5, x = - 211 + 5

Decimal Notation

x = 11.63324 \dots, x = - 1.63324 \dots

Solution steps

(x - 5)^{2} + 5 = 49

Move

5

to the right side

(x - 5)^{2} = 44

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 44 : x = 211 + 5

Solve

x - 5 = - 44 : x = - 211 + 5

The solutions to the quadratic equation are:

x = 211 + 5, x = - 211 + 5

∣ 4 - 3 x ∣ = 4

\frac{x - 5}{x + 3} > 0

\frac{- 48}{6}

54 x^{3} - 250 y^{3}

6 x^{4} y - 4 x^{2} y^{2} + 2 x^{2} y^{3}

What are the solutions to the equation (x-5)^2+5=49 ?
The solutions to the equation (x-5)^2+5=49 are x=2sqrt(11)+5,x=-2sqrt(11)+5
Find the zeros of (x-5)^2+5=49
The zeros of (x-5)^2+5=49 are x=2sqrt(11)+5,x=-2sqrt(11)+5