What is the answer to log_{r}(16)=4log_{r}(2) ?

The answer to log_{r}(16)=4log_{r}(2) is 0 1

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log_{r}(16)=4log_{r}(2)

lo g_{r} (16) = 4 lo g_{r} (2)

0 < r < 1 or r > 1

Solution steps

lo g_{r} (16) = 4 lo g_{r} (2)

Apply log rules

16 = 16

Both sides are equal

True for all r

Verify Solutions:

0 < r < 1 or r > 1

The solution is

0 < r < 1 or r > 1

lo g_{4} (2 x - 3) = 2

lo g_{7} (5 x - 1) = lo g_{7} (x + 7)

x, ln (x) = 2 ln (y)

lo g_{x} (e^{2}) = 2

lo g_{2} (x - 3) = lo g_{2} (9)

What is the answer to log_{r}(16)=4log_{r}(2) ?
The answer to log_{r}(16)=4log_{r}(2) is 0<r<1\lor r>1
Solve for r: log_{r}(16)=4log_{r}(2)
The solution is 0<r<1\lor r>1