What is the answer to ln(x+6)-ln(2x-1)=0 ?

The answer to ln(x+6)-ln(2x-1)=0 is x=7

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ln(x+6)-ln(2x-1)=0

ln (x + 6) - ln (2 x - 1) = 0

x = 7

Solution steps

ln (x + 6) - ln (2 x - 1) = 0

Add

ln (2 x - 1)

to both sides

ln (x + 6) - ln (2 x - 1) + ln (2 x - 1) = 0 + ln (2 x - 1)

Simplify

ln (x + 6) = ln (2 x - 1)

Apply log rules

x + 6 = 2 x - 1

Solve

x + 6 = 2 x - 1 : x = 7

x = 7

Verify Solutions:

x = 7

True

The solution is

x = 7

lo g_{2} (x - 1) = 8

lo g_{10} (2 x) = 2

ln (x) + ln (x + 1) = ln (2)

lo g_{5} (x) = 4 lo g_{x} (5)

0 = 2 (x + 1) ln (x + 1) + (x + 1)

What is the answer to ln(x+6)-ln(2x-1)=0 ?
The answer to ln(x+6)-ln(2x-1)=0 is x=7
Solve for x: ln(x+6)-ln(2x-1)=0
The solution is x=7