What is the answer to 0.82=log_{10}(x) ?

The answer to 0.82=log_{10}(x) is x=10^{0.82}

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0.82=log_{10}(x)

0.82 = lo g_{10} (x)

x = 1 0^{0.82}

Decimal Notation

x = 6.60693 \dots

Solution steps

0.82 = lo g_{10} (x)

Apply log rules

1 0^{0.82} = x

Switch sides

x = 1 0^{0.82}

lo g_{3} (- 2 x - 3) = 2

lo g_{b} (8) = \frac{3}{2}

x, ln (x^{2} + 4 y^{2}) = 0

lo g_{x} (x + 6) = 2

2 lo g_{4} (x) - lo g_{4} (x + 24) = 1

What is the answer to 0.82=log_{10}(x) ?
The answer to 0.82=log_{10}(x) is x=10^{0.82}
Solve for x: 0.82=log_{10}(x)
The solution is x=10^{0.82}