What is the answer to 0.234=ln(x^2) ?

The answer to 0.234=ln(x^2) is x=sqrt(e^{0.234)},x=-sqrt(e^{0.234)}

Solve for x: 0.234=ln(x^2)

The solution is x=sqrt(e^{0.234)},x=-sqrt(e^{0.234)}

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0.234 = ln (x^{2})

x = e^{0.234}, x = - e^{0.234}

Decimal Notation

x = 1.12411 \dots, x = - 1.12411 \dots

Solution steps

0.234 = ln (x^{2})

Apply log rules

e^{0.234} = x^{2}

Solve

e^{0.234} = x^{2} : x = e^{0.234}, x = - e^{0.234}

x = e^{0.234}, x = - e^{0.234}

ln (x) = 2.021

lo g_{2} (x) - lo g_{8} (x) = 6

lo g_{3} (x + 2) = 4

ln (b) = 5

ln (x) = a

What is the answer to 0.234=ln(x^2) ?
The answer to 0.234=ln(x^2) is x=sqrt(e^{0.234)},x=-sqrt(e^{0.234)}
Solve for x: 0.234=ln(x^2)
The solution is x=sqrt(e^{0.234)},x=-sqrt(e^{0.234)}