What is the answer to log_{10}((x+2)^2)=2,x>0 ?

The answer to log_{10}((x+2)^2)=2,x>0 is x=8,x=-12

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log_{10}((x+2)^2)=2,x>0

lo g_{10} ((x + 2)^{2}) = 2, x > 0

x = 8, x = - 12

Solution steps

lo g_{10} ((x + 2)^{2}) = 2

Apply log rules

(x + 2)^{2} = 100

Solve

(x + 2)^{2} = 100 : x = 8, x = - 12

x = 8, x = - 12

Check constrains

x = 8, x = - 12

lo g_{3} (x) = lo g_{9} (4)

ln (3 - x) = 4 + ln (x)

10 - 4 ln (9 - 8 x) = 6

lo g_{10} (1 - x) = - 1

2 ln (2 x - 10) + 19 = 13

What is the answer to log_{10}((x+2)^2)=2,x>0 ?
The answer to log_{10}((x+2)^2)=2,x>0 is x=8,x=-12
Solve for x: log_{10}((x+2)^2)=2,x>0
The solution is x=8,x=-12