What is the answer to ln(3x+4)-ln(2x+1)=5 ?

The answer to ln(3x+4)-ln(2x+1)=5 is x=(e^5-4)/(3-2e^5)

Solve for x: ln(3x+4)-ln(2x+1)=5

The solution is x=(e^5-4)/(3-2e^5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln (3 x + 4) - ln (2 x + 1) = 5

x = \frac{e ^{5} - 4}{3 - 2 e ^{5}}

Decimal Notation

x = - 0.49149 \dots

Solution steps

ln (3 x + 4) - ln (2 x + 1) = 5

Add

ln (2 x + 1)

to both sides

ln (3 x + 4) - ln (2 x + 1) + ln (2 x + 1) = 5 + ln (2 x + 1)

Simplify

ln (3 x + 4) = 5 + ln (2 x + 1)

Apply log rules

3 x + 4 = e^{5} (2 x + 1)

Solve

3 x + 4 = e^{5} (2 x + 1) : x = \frac{e ^{5} - 4}{3 - 2 e ^{5}}

x = \frac{e ^{5} - 4}{3 - 2 e ^{5}}

Verify Solutions:

x = \frac{e ^{5} - 4}{3 - 2 e ^{5}}

True

The solution is

x = \frac{e ^{5} - 4}{3 - 2 e ^{5}}

lo g_{3} (lo g_{5} (x^{2})) = 1

- 1 = 10 lo g_{10} (x)

lo g_{10} (x) 9 = 2

lo g_{10} (x - 1) = 0

3 = lo g_{2} (x)

What is the answer to ln(3x+4)-ln(2x+1)=5 ?
The answer to ln(3x+4)-ln(2x+1)=5 is x=(e^5-4)/(3-2e^5)
Solve for x: ln(3x+4)-ln(2x+1)=5
The solution is x=(e^5-4)/(3-2e^5)