What is the answer to log_{3}(x^2-3x+1)=0 ?

The answer to log_{3}(x^2-3x+1)=0 is x=3,x=0

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log_{3}(x^2-3x+1)=0

lo g_{3} (x^{2} - 3 x + 1) = 0

x = 3, x = 0

Solution steps

lo g_{3} (x^{2} - 3 x + 1) = 0

Apply log rules

x^{2} - 3 x + 1 = 1

Solve

x^{2} - 3 x + 1 = 1 : x = 3, x = 0

x = 3, x = 0

lo g_{10} (x) = 0.61

lo g_{10} (8) = 3 - 3 lo g_{10} (x)

0.891 = ln (x^{3})

x, ln (y) = 4 ln (x) + c

ln (3 x - 18) = 8

What is the answer to log_{3}(x^2-3x+1)=0 ?
The answer to log_{3}(x^2-3x+1)=0 is x=3,x=0
Solve for x: log_{3}(x^2-3x+1)=0
The solution is x=3,x=0