What is the answer to solvefor x,ln(y)=2ln(x) ?

The answer to solvefor x,ln(y)=2ln(x) is x=e^{(ln(y))/2} {y>0}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,ln(y)=2ln(x)

solve for

x, ln (y) = 2 ln (x)

x = e^{\frac{l n ( y )}{2}} {y > 0}

Solution steps

ln (y) = 2 ln (x)

Switch sides

2 ln (x) = ln (y)

Divide both sides by

2

ln (x) = \frac{ln ( y )}{2}

Apply log rules

x = e^{\frac{l n ( y )}{2}}

Verify Solutions:

x = e^{\frac{l n ( y )}{2}} {y > 0}

The solution is

x = e^{\frac{l n ( y )}{2}} {y > 0}

ln (x) + ln (x + 1) = ln (12)

lo g_{3} (x) = - \frac{2}{3}

lo g_{5} (x) + 2 = lo g_{5} (7)

lo g_{x} (\frac{1}{81}) = 2

lo g_{2} (3 x) = 10

What is the answer to solvefor x,ln(y)=2ln(x) ?
The answer to solvefor x,ln(y)=2ln(x) is x=e^{(ln(y))/2} {y>0}