What is the answer to log_{sqrt(17)}(x^2-2x-2)=0 ?

The answer to log_{sqrt(17)}(x^2-2x-2)=0 is x=3,x=-1

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log_{sqrt(17)}(x^2-2x-2)=0

lo g_{17} (x^{2} - 2 x - 2) = 0

x = 3, x = - 1

Solution steps

lo g_{17} (x^{2} - 2 x - 2) = 0

Apply log rules

x^{2} - 2 x - 2 = 1

Solve

x^{2} - 2 x - 2 = 1 : x = 3, x = - 1

x = 3, x = - 1

lo g_{5} (x^{2} + 16) = 2

4 x = ln (x)

lo g_{x} (64) = - 3

lo g_{10} (x) = 1000

lo g_{2} (\frac{x}{32000}) = 0.7

What is the answer to log_{sqrt(17)}(x^2-2x-2)=0 ?
The answer to log_{sqrt(17)}(x^2-2x-2)=0 is x=3,x=-1
Solve for x: log_{sqrt(17)}(x^2-2x-2)=0
The solution is x=3,x=-1