What is the answer to log_{6}(x+1)+log_{6}(2)=1 ?

The answer to log_{6}(x+1)+log_{6}(2)=1 is x=2

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log_{6}(x+1)+log_{6}(2)=1

lo g_{6} (x + 1) + lo g_{6} (2) = 1

x = 2

Solution steps

lo g_{6} (x + 1) + lo g_{6} (2) = 1

Move

lo g_{6} (2)

to the right side

lo g_{6} (x + 1) = 1 - lo g_{6} (2)

Apply log rules

x + 1 = 3

Solve

x + 1 = 3 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

1 + 2 lo g_{4} (t + 1) = 2 lo g_{2} (t)

lo g_{5} (3 x - 2) = 1 + lo g_{5} (x - 4)

ln (x + 5) = 2

lo g_{8} (x^{3}) - lo g_{x} (8) = 2

20 = 20 lo g_{10} (x)

What is the answer to log_{6}(x+1)+log_{6}(2)=1 ?
The answer to log_{6}(x+1)+log_{6}(2)=1 is x=2
Solve for x: log_{6}(x+1)+log_{6}(2)=1
The solution is x=2