What is the answer to ln(x-5)+ln(x+3)=1 ?

The answer to ln(x-5)+ln(x+3)=1 is x=(2+sqrt(4e+64))/2

Solve for x: ln(x-5)+ln(x+3)=1

The solution is x=(2+sqrt(4e+64))/2

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ln (x - 5) + ln (x + 3) = 1

x = \frac{2 + 4 e + 64}{2}

Decimal Notation

x = 5.32646 \dots

Solution steps

ln (x - 5) + ln (x + 3) = 1

Apply log rules

(x - 5) (x + 3) = e

Solve

(x - 5) (x + 3) = e : x = \frac{2 + 4 e + 64}{2}, x = \frac{2 - 4 e + 64}{2}

x = \frac{2 + 4 e + 64}{2}, x = \frac{2 - 4 e + 64}{2}

Verify Solutions:

x = \frac{2 + 4 e + 64}{2}

True

, x = \frac{2 - 4 e + 64}{2}

False

The solution is

x = \frac{2 + 4 e + 64}{2}

lo g_{2} (x + 2) - lo g_{2} (x) = 2

lo g_{3} (x + 6) - lo g_{3} (x - 2) = 1

lo g_{3} (2 x + 1) - lo g_{3} (x - 7) = 2

lo g_{4} (x + 6) + lo g_{4} (x + 18) = 3

lo g_{7} (x) = 2.5

What is the answer to ln(x-5)+ln(x+3)=1 ?
The answer to ln(x-5)+ln(x+3)=1 is x=(2+sqrt(4e+64))/2
Solve for x: ln(x-5)+ln(x+3)=1
The solution is x=(2+sqrt(4e+64))/2