What is the answer to 2ln(-2x)=0 ?

The answer to 2ln(-2x)=0 is x=-1/2

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2ln(-2x)=0

2 ln (- 2 x) = 0

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

2 ln (- 2 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

ln (- 2 x) = 0

Solve

ln (- 2 x) = 0 : x = - \frac{1}{2}

Verify Solutions:

x = - \frac{1}{2}

True

The solution is

x = - \frac{1}{2}

lo g_{2} (y) = 5

ln (2 x - 1) = 3

ln (x + 1) - ln (2 x - 3) = ln (2)

lo g_{10} (x) = 3.145

y, x = y + ln (y)