What are the solutions to the equation (x-2)^2+3=0 ?

The solutions to the equation (x-2)^2+3=0 are x=sqrt(3)i+2,x=-sqrt(3)i+2

Find the zeros of (x-2)^2+3=0

The zeros of (x-2)^2+3=0 are x=sqrt(3)i+2,x=-sqrt(3)i+2

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(x - 2)^{2} + 3 = 0

x = 3 i + 2, x = - 3 i + 2

Solution steps

(x - 2)^{2} + 3 = 0

Move

3

to the right side

(x - 2)^{2} = - 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 3 : x = 3 i + 2

Solve

x - 2 = - - 3 : x = - 3 i + 2

The solutions to the quadratic equation are:

x = 3 i + 2, x = - 3 i + 2

1 - \frac{2}{3}

lo g_{3} (3^{4})

4 a^{3} b^{2} \cdot 3 a^{6} b^{5}

6 x^{2} = x

12 \cdot \frac{2}{3}

What are the solutions to the equation (x-2)^2+3=0 ?
The solutions to the equation (x-2)^2+3=0 are x=sqrt(3)i+2,x=-sqrt(3)i+2
Find the zeros of (x-2)^2+3=0
The zeros of (x-2)^2+3=0 are x=sqrt(3)i+2,x=-sqrt(3)i+2