What is the answer to solvefor y,3ln(t)-ln(y)=4 ?

The answer to solvefor y,3ln(t)-ln(y)=4 is y= 1/(e^4)t^3 {t>0}

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solvefor y,3ln(t)-ln(y)=4

solve for

y, 3 ln (t) - ln (y) = 4

y = \frac{1}{e ^{4}} t^{3} {t > 0}

Solution steps

3 ln (t) - ln (y) = 4

Move

3 ln (t)

to the right side

- ln (y) = 4 - 3 ln (t)

Divide both sides by

- 1

ln (y) = - 4 + 3 ln (t)

Apply log rules

y = \frac{1}{e ^{4}} t^{3}

Verify Solutions:

y = \frac{1}{e ^{4}} t^{3} {t > 0}

The solution is

y = \frac{1}{e ^{4}} t^{3} {t > 0}

ln (12) - ln (x - 1) = ln (x - 2)

11.5 = - lo g_{10} (x)

ln (x - 1) - 1 = - 1 + ln (- 3 x + 2)

4 ln (x + 2) = 24

2 ln (7 x) = 18

What is the answer to solvefor y,3ln(t)-ln(y)=4 ?
The answer to solvefor y,3ln(t)-ln(y)=4 is y= 1/(e^4)t^3 {t>0}