What is the answer to 4ln(x)=x^2ln(x) ?

The answer to 4ln(x)=x^2ln(x) is x=1,x=2

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4ln(x)=x^2ln(x)

4 ln (x) = x^{2} ln (x)

x = 1, x = 2

Solution steps

4 ln (x) = x^{2} ln (x)

Move

x^{2} ln (x)

to the left side

4 ln (x) - x^{2} ln (x) = 0

Factor

4 ln (x) - x^{2} ln (x) : ln (x) (4 - x^{2})

ln (x) (4 - x^{2}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

ln (x) = 0 or 4 - x^{2} = 0

Solve

ln (x) = 0 : x = 1

Solve

4 - x^{2} = 0 : x = 2, x = - 2

Verify Solutions:

x = 1

True

, x = 2

True

, x = - 2

False

The solutions are

x = 1, x = 2

ln (2 x - 3) = ln (10) - ln (x - 2)

2 ln (3 x) = 4

0 = ln (x - 1) - 1

20 lo g_{10} (x) = 0

lo g_{2} (x) + lo g_{4} (4 x) = - 2

What is the answer to 4ln(x)=x^2ln(x) ?
The answer to 4ln(x)=x^2ln(x) is x=1,x=2
Solve for x: 4ln(x)=x^2ln(x)
The solution is x=1,x=2