What is the answer to 5ln(4x-10)+11=1 ?

The answer to 5ln(4x-10)+11=1 is x=(1+10e^2)/(4e^2)

Solve for x: 5ln(4x-10)+11=1

The solution is x=(1+10e^2)/(4e^2)

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5 ln (4 x - 10) + 11 = 1

x = \frac{1 + 10 e ^{2}}{4 e ^{2}}

Decimal Notation

x = 2.53383 \dots

Solution steps

5 ln (4 x - 10) + 11 = 1

Move

11

to the right side

5 ln (4 x - 10) = - 10

Divide both sides by

5

ln (4 x - 10) = - 2

Apply log rules

4 x - 10 = \frac{1}{e ^{2}}

Solve

4 x - 10 = \frac{1}{e ^{2}} : x = \frac{1 + 10 e ^{2}}{4 e ^{2}}

x = \frac{1 + 10 e ^{2}}{4 e ^{2}}

Verify Solutions:

x = \frac{1 + 10 e ^{2}}{4 e ^{2}}

True

The solution is

x = \frac{1 + 10 e ^{2}}{4 e ^{2}}

lo g_{10} (2 x - 4) = 5

lo g_{3} (y) = 4

ln (3 x + 4) = 5

lo g_{5} (x^{2} - 3) = 0

lo g_{4} (- 3 x + 8) = 1

What is the answer to 5ln(4x-10)+11=1 ?
The answer to 5ln(4x-10)+11=1 is x=(1+10e^2)/(4e^2)
Solve for x: 5ln(4x-10)+11=1
The solution is x=(1+10e^2)/(4e^2)