What is the answer to log_{4}(x+4)+log_{4}(x-2)=2 ?

The answer to log_{4}(x+4)+log_{4}(x-2)=2 is x=4

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log_{4}(x+4)+log_{4}(x-2)=2

lo g_{4} (x + 4) + lo g_{4} (x - 2) = 2

x = 4

Solution steps

lo g_{4} (x + 4) + lo g_{4} (x - 2) = 2

Apply log rules

(x + 4) (x - 2) = 16

Solve

(x + 4) (x - 2) = 16 : x = 4, x = - 6

x = 4, x = - 6

Verify Solutions:

x = 4

True

, x = - 6

False

The solution is

x = 4

lo g_{x} (64) = \frac{3}{4}

ln (x^{2}) = 9

lo g_{10} (x) - lo g_{10} (2) = 1

lo g_{6} (8) + 3 = lo g_{6} (x)

x, ln (x^{2} + 4 y^{2}) = 1

What is the answer to log_{4}(x+4)+log_{4}(x-2)=2 ?
The answer to log_{4}(x+4)+log_{4}(x-2)=2 is x=4
Solve for x: log_{4}(x+4)+log_{4}(x-2)=2
The solution is x=4