What is the answer to 5=log_{4}(x)+log_{4}(x+1) ?

The answer to 5=log_{4}(x)+log_{4}(x+1) is x=(-1+sqrt(4097))/2

Solve for x: 5=log_{4}(x)+log_{4}(x+1)

The solution is x=(-1+sqrt(4097))/2

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5 = lo g_{4} (x) + lo g_{4} (x + 1)

x = \frac{- 1 + 4097}{2}

Decimal Notation

x = 31.50390 \dots

Solution steps

5 = lo g_{4} (x) + lo g_{4} (x + 1)

Apply log rules

1024 = x (x + 1)

Solve

1024 = x (x + 1) : x = \frac{- 1 + 4097}{2}, x = \frac{- 1 - 4097}{2}

x = \frac{- 1 + 4097}{2}, x = \frac{- 1 - 4097}{2}

Verify Solutions:

x = \frac{- 1 + 4097}{2}

True

, x = \frac{- 1 - 4097}{2}

False

The solution is

x = \frac{- 1 + 4097}{2}

2 lo g_{6} (4 x) = 0

- ln (- 8 x - 8) - 4 = - 7

2 ln (x) = - x + 4 x

3 lo g_{2} (x - 1) = lo g_{2} (27)

lo g_{a} (125) = 3

What is the answer to 5=log_{4}(x)+log_{4}(x+1) ?
The answer to 5=log_{4}(x)+log_{4}(x+1) is x=(-1+sqrt(4097))/2
Solve for x: 5=log_{4}(x)+log_{4}(x+1)
The solution is x=(-1+sqrt(4097))/2