What is the answer to ln(3x+2)+ln(x-1)=1 ?

The answer to ln(3x+2)+ln(x-1)=1 is x=(1+sqrt(12e+25))/6

Solve for x: ln(3x+2)+ln(x-1)=1

The solution is x=(1+sqrt(12e+25))/6

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ln (3 x + 2) + ln (x - 1) = 1

x = \frac{1 + 12 e + 25}{6}

Decimal Notation

x = 1.43179 \dots

Solution steps

ln (3 x + 2) + ln (x - 1) = 1

Apply log rules

(3 x + 2) (x - 1) = e

Solve

(3 x + 2) (x - 1) = e : x = \frac{1 + 12 e + 25}{6}, x = \frac{1 - 12 e + 25}{6}

x = \frac{1 + 12 e + 25}{6}, x = \frac{1 - 12 e + 25}{6}

Verify Solutions:

x = \frac{1 + 12 e + 25}{6}

True

, x = \frac{1 - 12 e + 25}{6}

False

The solution is

x = \frac{1 + 12 e + 25}{6}

0.45 = lo g_{10} (x)

lo g_{x} (64) = 1

lo g_{10} (x) = ln (x)

lo g_{2} (2 x + 3) = lo g_{2} (x + 7)

lo g_{10} (x) = 0.83

What is the answer to ln(3x+2)+ln(x-1)=1 ?
The answer to ln(3x+2)+ln(x-1)=1 is x=(1+sqrt(12e+25))/6
Solve for x: ln(3x+2)+ln(x-1)=1
The solution is x=(1+sqrt(12e+25))/6