What is the answer to log_{2}(sqrt(x^2+6x))=4 ?

The answer to log_{2}(sqrt(x^2+6x))=4 is x=-3+sqrt(265),x=-3-sqrt(265)

Solve for x: log_{2}(sqrt(x^2+6x))=4

The solution is x=-3+sqrt(265),x=-3-sqrt(265)

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lo g_{2} (x^{2} + 6 x) = 4

x = - 3 + 265, x = - 3 - 265

Decimal Notation

x = 13.27882 \dots, x = - 19.27882 \dots

Solution steps

lo g_{2} (x^{2} + 6 x) = 4

Apply log rules

x^{2} + 6 x = 16

Solve

x^{2} + 6 x = 16 : x = - 3 + 265, x = - 3 - 265

x = - 3 + 265, x = - 3 - 265

ln (\frac{x}{x - 2}) = 1

lo g_{2} (x - 2) + lo g_{2} (x + 4) = 4

lo g_{0.05} (x) = 3

x^{5} e^{- 3 l n (x)} + 4 x = 21

ln (x) + ln (x - 3 e) = ln (4) + 2

What is the answer to log_{2}(sqrt(x^2+6x))=4 ?
The answer to log_{2}(sqrt(x^2+6x))=4 is x=-3+sqrt(265),x=-3-sqrt(265)
Solve for x: log_{2}(sqrt(x^2+6x))=4
The solution is x=-3+sqrt(265),x=-3-sqrt(265)