What is the answer to log_{6}(x-4)=log_{6}(2x+8) ?

The answer to log_{6}(x-4)=log_{6}(2x+8) is No Solution for x\in\mathbb{R}

Solve for x: log_{6}(x-4)=log_{6}(2x+8)

The solution is No Solution for x\in\mathbb{R}

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lo g_{6} (x - 4) = lo g_{6} (2 x + 8)

No Solution for x \in R

Solution steps

lo g_{6} (x - 4) = lo g_{6} (2 x + 8)

Apply log rules

x - 4 = 2 x + 8

Solve

x - 4 = 2 x + 8 : x = - 12

x = - 12

Verify Solutions:

x = - 12

False

The solution is

No Solution for x \in R

ln (x) + ln (x + 3) = ln (20 - 5 x)

ln (x) = 2.3

lo g_{10} (x) = 2

2 lo g_{2} (x - 4) = 10

ln (x) = 0.3

What is the answer to log_{6}(x-4)=log_{6}(2x+8) ?
The answer to log_{6}(x-4)=log_{6}(2x+8) is No Solution for x\in\mathbb{R}
Solve for x: log_{6}(x-4)=log_{6}(2x+8)
The solution is No Solution for x\in\mathbb{R}