What are the solutions to the equation 3(x-4)^2+20=47 ?

The solutions to the equation 3(x-4)^2+20=47 are x=7,x=1

Find the zeros of 3(x-4)^2+20=47

The zeros of 3(x-4)^2+20=47 are x=7,x=1

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3 (x - 4)^{2} + 20 = 47

x = 7, x = 1

Solution steps

3 (x - 4)^{2} + 20 = 47

Move

20

to the right side

3 (x - 4)^{2} = 27

Divide both sides by

3

(x - 4)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 9 : x = 7

Solve

x - 4 = - 9 : x = 1

The solutions to the quadratic equation are:

x = 7, x = 1

2 x^{2} - 21 x - 11

6 (x - 7) - 7 (x - 6) = x + 6 - (x - 4)

2 x = x - 1

2 y^{2} - 9 y + 7

15 - 4 x - 4 x^{2}

What are the solutions to the equation 3(x-4)^2+20=47 ?
The solutions to the equation 3(x-4)^2+20=47 are x=7,x=1
Find the zeros of 3(x-4)^2+20=47
The zeros of 3(x-4)^2+20=47 are x=7,x=1