What is the answer to ln(1-x)+ln(3-x)=ln(8) ?

The answer to ln(1-x)+ln(3-x)=ln(8) is x=-1

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ln(1-x)+ln(3-x)=ln(8)

ln (1 - x) + ln (3 - x) = ln (8)

x = - 1

Solution steps

ln (1 - x) + ln (3 - x) = ln (8)

Apply log rules

(1 - x) (3 - x) = 8

Solve

(1 - x) (3 - x) = 8 : x = 5, x = - 1

x = 5, x = - 1

Verify Solutions:

x = 5

False

, x = - 1

True

The solution is

x = - 1

4 lo g_{4} (2) = lo g_{4} (x - 2)

lo g_{10} (x) + lo g_{10} (2) = 1

lo g_{3} (x) + 4 = lo g_{3} (8)

lo g_{9} (x) = - \frac{3}{2}

ln (4 x) = - 1

What is the answer to ln(1-x)+ln(3-x)=ln(8) ?
The answer to ln(1-x)+ln(3-x)=ln(8) is x=-1
Solve for x: ln(1-x)+ln(3-x)=ln(8)
The solution is x=-1