What is the answer to ln(x)+ln(x-2)=5 ?

The answer to ln(x)+ln(x-2)=5 is x=(2+sqrt(4+4e^5))/2

Solve for x: ln(x)+ln(x-2)=5

The solution is x=(2+sqrt(4+4e^5))/2

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ln (x) + ln (x - 2) = 5

x = \frac{2 + 4 + 4 e ^{5}}{2}

Decimal Notation

x = 13.22346 \dots

Solution steps

ln (x) + ln (x - 2) = 5

Apply log rules

x (x - 2) = e^{5}

Solve

x (x - 2) = e^{5} : x = \frac{2 + 4 + 4 e ^{5}}{2}, x = \frac{2 - 4 + 4 e ^{5}}{2}

x = \frac{2 + 4 + 4 e ^{5}}{2}, x = \frac{2 - 4 + 4 e ^{5}}{2}

Verify Solutions:

x = \frac{2 + 4 + 4 e ^{5}}{2}

True

, x = \frac{2 - 4 + 4 e ^{5}}{2}

False

The solution is

x = \frac{2 + 4 + 4 e ^{5}}{2}

lo g_{9} (4) + lo g_{3} (x) = 3

lo g_{2} (y) = - 3

0 = - lo g_{10} (x)

lo g_{6} (x) = \frac{5}{3}

0.62 = ln (y)

What is the answer to ln(x)+ln(x-2)=5 ?
The answer to ln(x)+ln(x-2)=5 is x=(2+sqrt(4+4e^5))/2
Solve for x: ln(x)+ln(x-2)=5
The solution is x=(2+sqrt(4+4e^5))/2