What is the answer to log_{7}(x)+log_{8}(x)=1 ?

The answer to log_{7}(x)+log_{8}(x)=1 is x=8^{(log_{8}(7))/(1+log_{8)(7)}}

Solve for x: log_{7}(x)+log_{8}(x)=1

The solution is x=8^{(log_{8}(7))/(1+log_{8)(7)}}

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lo g_{7} (x) + lo g_{8} (x) = 1

x = 8^{\frac{l o g _{8} ( 7 )}{1 + l o g _{8} ( 7 )}}

Decimal Notation

x = 2.73253 \dots

Solution steps

lo g_{7} (x) + lo g_{8} (x) = 1

Apply log rules

x = 8^{\frac{l o g _{8} ( 7 )}{1 + l o g _{8} ( 7 )}}

Verify Solutions:

x = 8^{\frac{l o g _{8} ( 7 )}{1 + l o g _{8} ( 7 )}}

True

The solution is

x = 8^{\frac{l o g _{8} ( 7 )}{1 + l o g _{8} ( 7 )}}

ln (x + 7) = 2

2 lo g_{8} (5) = lo g_{8} (x)

lo g_{e} (x^{2}) + lo g_{7} (x) = 2

0.48 = lo g_{10} (x)

ln (y^{2} - 1) - ln (y + 1) = 3

What is the answer to log_{7}(x)+log_{8}(x)=1 ?
The answer to log_{7}(x)+log_{8}(x)=1 is x=8^{(log_{8}(7))/(1+log_{8)(7)}}
Solve for x: log_{7}(x)+log_{8}(x)=1
The solution is x=8^{(log_{8}(7))/(1+log_{8)(7)}}