What is the answer to solvefor x,-ln(y)=ln(x)+c ?

The answer to solvefor x,-ln(y)=ln(x)+c is x=(e^{-c})/y

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solvefor x,-ln(y)=ln(x)+c

solve for

x, - ln (y) = ln (x) + c

x = \frac{e ^{- c}}{y}

Solution steps

- ln (y) = ln (x) + c

Switch sides

ln (x) + c = - ln (y)

Move

c

to the right side

ln (x) = - ln (y) - c

Apply log rules

x = \frac{e ^{- c}}{y}

lo g_{4} (9 x - 4) = 2

3 ln (4 x + 8) - 13 = - 22

lo g_{2} (x) - lo g_{4} (x) = 3

lo g_{2} (2 x + 1) - lo g_{2} (x - 1) = 4

lo g_{5} (2 x - 1) = 3

What is the answer to solvefor x,-ln(y)=ln(x)+c ?
The answer to solvefor x,-ln(y)=ln(x)+c is x=(e^{-c})/y