What is the answer to log_{2}(4x)-log_{2}(x^2)=4 ?

The answer to log_{2}(4x)-log_{2}(x^2)=4 is x= 1/4

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log_{2}(4x)-log_{2}(x^2)=4

lo g_{2} (4 x) - lo g_{2} (x^{2}) = 4

x = \frac{1}{4}

Decimal Notation

x = 0.25

Solution steps

lo g_{2} (4 x) - lo g_{2} (x^{2}) = 4

Apply log rules

x = \frac{1}{4}

Verify Solutions:

x = \frac{1}{4}

True

The solution is

x = \frac{1}{4}

2 x \cdot ln (x) + x = 0

lo g_{2} (3 x - 1) = lo g_{4} (x + 8)

0.79 = lo g_{10} (x)

0 = lo g_{2} (x)

lo g_{x} (\frac{16}{25}) = 2

What is the answer to log_{2}(4x)-log_{2}(x^2)=4 ?
The answer to log_{2}(4x)-log_{2}(x^2)=4 is x= 1/4
Solve for x: log_{2}(4x)-log_{2}(x^2)=4
The solution is x= 1/4