What is the answer to log_{2}(-3x+1)=3 ?

The answer to log_{2}(-3x+1)=3 is x=-7/3

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log_{2}(-3x+1)=3

lo g_{2} (- 3 x + 1) = 3

x = - \frac{7}{3}

Decimal Notation

x = - 2.33333 \dots

Solution steps

lo g_{2} (- 3 x + 1) = 3

Apply log rules

- 3 x + 1 = 8

Solve

- 3 x + 1 = 8 : x = - \frac{7}{3}

x = - \frac{7}{3}

lo g_{3} (x) = 7

lo g_{\frac{1}{2}} (x) = 4

- 2 = ln (x)

1 + ln (x) = 0

2 lo g_{3} (x) = 3 lo g_{2} (3)

What is the answer to log_{2}(-3x+1)=3 ?
The answer to log_{2}(-3x+1)=3 is x=-7/3
Solve for x: log_{2}(-3x+1)=3
The solution is x=-7/3