What is the answer to log_{3}(x+2)+log_{3}(x-4)=3 ?

The answer to log_{3}(x+2)+log_{3}(x-4)=3 is x=7

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log_{3}(x+2)+log_{3}(x-4)=3

lo g_{3} (x + 2) + lo g_{3} (x - 4) = 3

x = 7

Solution steps

lo g_{3} (x + 2) + lo g_{3} (x - 4) = 3

Apply log rules

(x + 2) (x - 4) = 27

Solve

(x + 2) (x - 4) = 27 : x = 7, x = - 5

x = 7, x = - 5

Verify Solutions:

x = 7

True

, x = - 5

False

The solution is

x = 7

(ln (x - 1)) (ln (x - 1) - 2) = - 1

lo g_{10} (3 x) + lo g_{10} (5) = 1

11 = - lo g_{10} (x)

2 ln (x) = (ln (x))^{- 1} + 1

lo g_{2} (y) = 2

What is the answer to log_{3}(x+2)+log_{3}(x-4)=3 ?
The answer to log_{3}(x+2)+log_{3}(x-4)=3 is x=7
Solve for x: log_{3}(x+2)+log_{3}(x-4)=3
The solution is x=7